Would you survive crossing the event horizon? Set your height and tidal acceleration tolerance, then slide the black hole mass. The answer depends entirely on the IMBH being massive enough.
Human centrifuge limit ~8–12g (brief). "Survivable crossing" means tidal stretching force across your body at the horizon is below your tolerance.
At your current settings (h = 1.8 m, tolerance = 10 g = 98 m/s²), the minimum survivable black hole mass is:
The differential gravitational acceleration across a body of height h at distance r from a mass M: Δa = 2GMh / r³. At the Schwarzschild horizon r = r_s = 2GM/c², substituting: Δa = c⁶h / (4G²M²). This scales as M⁻², so more massive black holes have gentler tidal forces at their horizon.
Setting Δa ≤ a_tol and solving for M: M_crit = c³/(2G) × √(h/a_tol) in SI units. For h = 1.8 m and a_tol = 1g = 9.8 m/s²: M_crit ≈ 1380 M☉. For a_tol = 10g: M_crit ≈ 437 M☉.
A radially infalling observer in Schwarzschild spacetime reaches the singularity in finite proper time (Misner, Thorne & Wheeler 1973, Box 31.2): τ = πGM/c³. Numerically: τ ≈ 1.545 × 10⁻⁵ × (M/M☉) seconds. For the ω Cen IMBH at 7100 M☉: τ ≈ 0.11 seconds.
From the perspective of a distant observer, a falling object appears to freeze near the horizon (Schwarzschild coordinates diverge). The coordinate fall time shown is an estimate of when the signal from the infalling observer effectively ceases to reach external observers.